Question 1145140
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<pre>
First addend,  {{{(x^5 - 6x + 7)^2019}}},  gives the remainder  (-1)^2019 = -1,  when divided by x^5 - 6x + 8.   OBVIOUSLY.


Second addend,  {{{(x^5 - 6x + 9)^2020}}},  gives the remainder  1^2020 = 1,  when divided by x^5 - 6x + 8.   OBVIOUSLY.


Third addend,  {{{5x^5 - 30x + 50}}},  gives the remainder  42,  when divided by x^5 - 6x + 8.   OBVIOUSLY.


Thus we know all three partial remainders, and are in position to answer the question now.


<U>ANSWER</U>.  The remainder under the question is  -1 - 1 + 42 = 40.
</pre>


Solved, answered, explained and completed.



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Nice problem (!)  &nbsp;&nbsp;An Olympiad level (!)


Thanks for posting it : &nbsp;it was a pleasure to me to solve it &nbsp;(!)



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