Question 1145128
An acute angle is formed by two lines of slopes (1/2) and (2/11). What is the slope of the line which bisects the angle?
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Use the Origin as a point on both lines.
---> y = x/2 and y = 2x/11
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Plot the points A(2,1) for slope 1/2 and B(11,2) for slope 2/11.
Find a point C the same distance from the Origin as B on the line y = x/2
distance to B = 5sqrt(5)
distance to A = sqrt(5)
---> point C is 5 times point A = (10,5)
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Find the midpoint of BC = (10.5,3.5)
Slope = y/x = 1/3