Question 1145118
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            The solution by @josmiceli is INCORRECT.


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              His equation (2) is incorrect, leading to wrong answer.
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&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;I came to bring the correct solution.



<U>Solution</U>


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From the condition, the width of rectangle  A  is  {{{11/x}}} cm.

                    the width of rectangle  B  is {{{11/(x+3)}}} cm.


Also, from the condition


    {{{11/x}}} - {{{11/(x+3)}}} = 2  cm.      (1)


It is your basic equation, and at this point, the setup is just completed.


Now my (and your) major task is to transform this equation to the standard form of a quadratic equation.


For it, multiply both side of the equation (1) by  x*(x+3).  You will get


    11*(x+3) - 11x = 2x*(x+3)

    11x + 33 - 11x = 2x^2 + 6x

    2x^2 + 6x - 33 = 0.


Your question is answered:  The equation in your post IS CORRECT.      <U>ANSWER</U>
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