Question 1145118
Let the width of B = {{{ y }}}
The width of A = {{{ y + 2 }}}
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(1) {{{ y*x = 11 }}}
(2) {{{ ( y + 2 )*( x + 3 ) = 11 }}}
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(1) {{{ y = 11/x }}}
and
{2} {{{ y + 2 = 11/( x + 3 ) }}}
(2) {{{ y = 11/( x + 3 ) - 2 }}}
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Set (1) = (2)
{{{ 11/x = 11/( x + 3 ) - 2 }}}
Multiply both sides by {{{ x*( x + 3 ) }}}
{{{ 11*( x + 3 ) = 11x - 2x*( x + 3 ) }}}
{{{ 11x + 33 = 11x - 2x^2 - 6x }}}
{{{ 33 = -2x^2 - 6x }}}
{{{ 2x^2 + 6x + 33 = 0 }}}
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The sign of the constant term is different. Check my math.