Question 105254
Let the vertex be (0,-1/2), (h,k)
Let c=k (because I am more used to using k)
y=a(x-h)^2+k
y=a(x-0)^2-1/2
y(2)=5/2
5/2=a(2)^2-1/2
5/2=4a-1/2
4a=3
a=3/4
y=(3/4)x^2-1/2
Ed
{{{graph(500,500,-10,10,-10,10,(3/4)x^2-(1/2))}}}