Question 1144735
m apples
p pears
m+p, total pieces of fruit


{{{(2/3)m=(3/4)p}}}


{{{(2/3)(4/3)m=p}}}


{{{p=(8/9)m}}}


Total quantity rotten fruit, {{{2(2/3)m=(4/3)m}}}.


Total fruit in box, {{{m+p=m+(8/9)m=(9/9)m+(8/9)m=(17/9)m}}}.


Fraction of fruit rotten:
{{{(4/3)/(17/9)}}}

{{{(4/1)/(17/3)}}}


{{{12/17}}}