Question 1144639
<br>
(a) You can draw the diagram....<br>
(b) (40*35)+1000 = 1400+1000 = 2400<br>
(c) (40+4x)(35+x) = 2400<br>
(d)
{{{(40+4x)(35+x) = 2400}}}  original equation
{{{(10+x)(35+x) = 600}}}    factor out the common factor of 4 from the first expression to keep the numbers smaller
{{{x^2+45x+350 = 600}}}
{{{x^2+45x-250 = 0}}}
{{{(x+50)(x-5) = 0}}}
{{{x = -50}}} or {{{x = 5}}}<br>
Clearly the -50 makes no sense in the problem; so x=5.<br>
The dimensions of the large field are
length: 40+4(5) = 60
width: 35+5 = 40