Question 1144624
Let {{{ d }}} = number of dimes
Let {{{ n }}} = number of nickels
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(1) {{{ n + d = 20 }}}
(2) {{{ 5n + 10d = 135 }}} ( in cents )
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(2) {{{ n + 2d = 27 }}}
Subtract (1) from (2)
{{{ d = 7 }}}
and
(1) {{{ n + 7 = 20 }}}
(1) {{{ n = 13 }}}
There are 7 dimes and 13 nickels
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check:
(2) {{{ 13 + 2*7 = 27 }}}
(2) {{{ 27 = 27 }}}
OK