Question 1144492
find x and y if, 3^(2x-y) = 1 and 16^x/4 = 8^3x-y 
assume it's
{{{3^((2x-y)) = 1}}}
In order for 3^ to = 1, 
2x-y = 0
2x = y

 and 
{{{16^((x/4)) = 8^((3x-y))}}} 
we can simplify this one
{{{2^(4(x/4)) = 2^(3(3x-y))}}}
which is
{{{2^x = 2^((9x-3y))}}}
therefore
x = 9x - 3y
3y = 9x - x
3y = 8x
y = {{{8/3}}}x
:
No solution