Question 15419
First of all lets make x=the number;
Now we know twice that number increased(+) by 3;
2x+3;
The result is(=);
8 lease(-) than 3 times that number;
3x-8;
So we have;
2x+3=3x-8
Subtract 3 from both sides;
2x+3-3=3x-8-3
2x=3x-11
Now subtract 3x from both sides;
2x-3x=3x-11-3x;
-x=-11
We do not want to leave the answer with -x so we will divide each side by -1;
x=11
Hope you understand
=)