Question 1144349
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \ h\ =\ 35f\ -\ 5t^2]?????


What is the *[tex \Large f]?  Yes, I know it is a typo.  But if you are too lazy to proofread your posts BEFORE you click on SEND, why should any of us exert any effort at all to help you?


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ h(t)\ =\ 35t\ -\ 5t^2]


is the almost proper function.  I say almost because using *[tex \Large 4.9\,\frac{m}{s^2}] as the value for one-half of the acceleration due to the gravitational force near the surface of the earth gives much more precise answer. Be that as it may, solve


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 35t\ -\ 5t^2\ =\ 12]


for both values of *[tex \Large t]
								
								
John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
<img src="http://c0rk.blogs.com/gr0undzer0/darwin-fish.jpg">
*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \  
								
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