Question 1144353
If the mean of 10 numbers = 132
   the total sum of 10 numbers= 132*10=1320

Now, let the removed number be 'a'
then total sum of left 9 numbers = 1320-a
     the mean of 9 numbers = {1320-a}/9
                     121 = {1320-a}/9 
                   121*9 = 1320-a
                   1089  = 1320-a
                      a  = 1320-1089
                      a  = 231 

231 is the required number.