Question 1144315
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Let x be the number of species A  and y be the number of species B.


The most difficult part of the solution is to setup the equations.


From the condition, you have these two equation


    4x + 1y = 19820  units of the first nutrient     (1)

    5x + 6y = 32090  units of the second nutrient    (2)


These equations -- this system of equations -- is your setup.


At this point, the setup is just completed.


Now you should solve it.

You can use different methods: Substitution, Elimination, using determinants (the Cramer's rule).


For example, you may express  y = 19820-4x from the first equation and then substitute it into the second


    5x + 6*(19820-4x) = 32090.


It gives you  x = {{{(32090-6*19820)/(5 - 24)}}} = 4570.

Then  y = 19820 - 4*4570 = 1540.


<U>ANSWER</U>.  4570 species of the type A  and  1540 species of the type B.
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If you want to see other similar solved problems, look into the lesson

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/coordinate/lessons/Roses-and-violets.lesson>Roses and vilolets</A> 

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/coordinate/Counting-calories-and-grams-of-fat-in-combined-food.lesson>Counting calories and grams of fat in combined food</A>

in this site.


Also, &nbsp;you have this free of charge online textbook in ALGEBRA-I in this site

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson>ALGEBRA-I - YOUR ONLINE TEXTBOOK</A>.


The referred lessons are the part of this online textbook under the topic "<U>Systems of two linear equations in two unknowns</U>".



Save the link to this online textbook together with its description


Free of charge online textbook in ALGEBRA-I
https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson


to your archive and use it when it is needed.