Question 1144270
5y/6+3y/4=19/12 find the value of y:
3y*(1/4)+5y*6^-1 = 19/12
3/4y+5y*6^-1 = 19/12
3/4y+5y*(1/6) = 19/12
3/4y+5/6y = 19/12
19/12y= 19/12
y = (19/12)/(19/12)
y = 1