Question 1144233
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<pre>
Let x be the amount, in dollars, at the money market account, paying 2%.


Then the amount at the saving account is (x-3000) dollars.


The equation, from the condition, is


    0.02x - 0.005*(x-3000) = 180  dollars   (interest minus interest equals to the given difference)


From the equation, express x and calculate


    x = {{{(180-0.005*3000)/(0.02-0.005)}}} = 11000.


<U>ANSWER</U>.  $11000 at the 2% account and (11000-3000) = 8000 dollars at the 0.5% account.


<U>CHECK</U>.   0.02*11000 - 0.005*8000 = 180 dollars.    ! Correct !
</pre>

Solved.


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It is a standard and typical problem on investments.


If you need more details,  &nbsp;or if you want to see other similar problems solved by different methods, &nbsp;look into the lesson 

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/coordinate/lessons/Using-systems-of-equations-to-solve-problems-on-investment.lesson>Using systems of equations to solve problems on investment</A>

in this site.


You will find there different approaches &nbsp;(using one equation or a system of two equations in two unknowns), &nbsp;as well as 
different methods of solution to the equations &nbsp;(Substitution, &nbsp;Elimination).


Also, &nbsp;you have this free of charge online textbook in ALGEBRA-I in this site

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson>ALGEBRA-I - YOUR ONLINE TEXTBOOK</A>.


The referred lesson is the part of this online textbook under the topic &nbsp;"<U>Systems of two linear equations in two unknowns</U>".



Save the link to this online textbook together with its description


Free of charge online textbook in ALGEBRA-I
https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson


to your archive and use it when it is needed.