Question 1144185
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There are   9  one-digit  numbers from 1    to   9 inclusively :    9 digits, in all.


There are  90 two-digit   numbers from 10   to  99 inclusively :  180 digits, in all.


There are 900 three-digit numbers from 100  to 999 inclusively : 2700 digits, in all.



Thus, 9 + 180 + 2700 = 2889 places are just occupied by one-digit, two-digits and three-digits numbers.



Starting from the position 2890, the four-digit are placed, each occupies 4 position.



Between  5000-th position and 2890-th position, there are  about  {{{(5000-2890+1)/4}}} =527.75, 

and more precisely, 527 four-digit numbers from 1000 to 1526, inclusively.


The next number is 1527, giving its third digit " 2 " at the 5000-th position.



<U>ANSWER</U>.  The digit " 2 " is at 5000-th position.
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