Question 1143819
This problem is solved using the Poisson distribution 
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The mean(u) for the distribution is 1.8 
:
P(X) = e^(-u) * u^x/x!
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(i) x = 0, then
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P(X=0) = e^(-1.8) * 1.8^0 / 0! = 0.1653
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(ii) P(at least one breakdown) = 1 - P(X=0) = 1 - 0.1653 = 0.8347
:
Note e = 2.71828 (but use your calculator's e button)
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