Question 1144138
.
<pre>

The product of the first three factors (terms) is


    2*sin(3x)*cos(3x) = sin(6x).


The fourth term is


    2*cos^2(3x)-1 = cos(6x).


Therefore


    2*sin(3x)*cos(3x)*(2cos^2 3x-1) = sin(6x)*cos(6x) = (1/2)*sin(12x).    <U>ANSWER</U>
</pre>

Solved.