Question 105143
{{{(x-1/3)(x+1/3)}}}

{{{x^2 + (1/3)x - (1/3)x - (1/3)(1/3)}}} 

since + {{{(1/3)x - (1/3 )x = 0}}}

we will have:

{{{x^2 - 1/9}}}     here, we can solve the quadratic function as:

{{{x^2 =1/9}}}

{{{x (1,2) = sqrt(1/9)}}}

{{{x(1,2) = (+-sqrt(1)/sqrt(9))}}}

{{{x(1)= + (1/3)}}}

{{{x(2) = - (1/3)}}}