Question 1144012
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(1) Foci at (-8,-7) and (-8,-13)<br>
So...
Transverse axis is vertical
General equation is {{{(y-k)^2/b^2-(x-h)^2/a^2=1}}}
c = 3
center (h,k) = (-8,-10)<br>
(2) Vertices at (-8,-9) and (-8,-11)<br>
So a = 1.<br>
Use c^2 = a^2+b^2 to determine b^2; then write the equation.