Question 1144021
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<pre>

Let x be the rate of the slower train, in mph;  then the rate of the faster train is (x+16).


The distance traveler by the slower train in 3 hours is 3x miles;

the distance traveler by the faster train in 3 hours is 3*(x+16)  miles.


The total distance is the sum of these values


    3x + 3*(x+16) = 570  miles.


Simplify and solve for x:


    3x + 3x + 48 = 570,

    6x = 570 - 48 = 522,

     x = {{{522/6}}} = 87.


<U>ANSWER</U>.  The slower train rate is 87 mph;  the faster train rate is 87+16 = 103 mph.


<U>CHECK</U>.   3*87 + 3*103 = 3*(87+107) = 3*190 = 570 miles.   ! Correct !
</pre>

Solved.


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