Question 98545
{{{log4(x-2)+ log4(x+6)=2}}}

{{{log(4x-8)*(4x+24)=log100}}}
{{{16(x^(2))+64x-192=100}}}

{{{16(x^(2))+64x-292=0}}}

x1={{{(-64+squareroot(4096+18688))/(32)}}}
  ={{{2.7}}}
x2={{{(-64-squareroot(4096+18688))/(32)}}}
  ={{{-6.7}}}