Question 1143788
<br>
{{{graph(400,400,-4,4,-8,8,4,6x-2x^3)}}}<br>
Algebra or a graphing calculator shows the points of intersection of the two graphs are at x=-2 and x=1; the cubic is below the constant in that interval.<br>
So the area to be found is<br>
integral from -2 to 1 of (4-(6x-2x^3)) dx<br>
I will assume since you are asking this question that you know how to evaluate that integral.