Question 1143778
<pre>
I think you meant either

(1) Simplify

{{{9/(3d-3)}}}

Factor the denominator by taking out 3

{{{9/(3(d-1))}}}

Divide top and bottom by 3:

{{{3/(d-1)}}}

or you meant

(2) Write as one fraction by combining the terms:

{{{9/(3d)-3}}}

In the first term, divide numerator and denominator by 3:

{{{3/d-3}}}

Write 3 as {{{3/1}}}

{{{3/d-3/1}}}

The LCD is d.  To make the 1 denominator become
the LCD, multiply it by 1 in the form {{{(d)/(d)}}}

{{{3/d-expr(3/1)expr((d)/(d))}}}

Multiply the numerators and denominators in the second fraction:

{{{3/d-(3d)/d}}}

Combine the numerators over the common denominator:

{{{(3-3d)/d}}}

If you like you may factor 3 out of the numerator, but it
is not necessary:

{{{(3(1-d))/d}}}

Edwin</pre>