Question 1143714

median= the average of the first and the last terms

S=( 11,12,13,14,15). 
{{{median=(11+15)/2=13}}}

The median of the set S is equal to the mean of the set T, which consists of 11 consecutive positive integers. What is the largest integer of the set T?

mean of the set T={{{13}}}

mean= median

the sum of the elements = the mean * # of elements
the sum of the elements = {{{13 *11=143}}}
the sum of the {{{11 }}}consecutive positive integers:
{{{x+x+1+x+2+x+3+x+4+x+5+x+6+x+7+x+8+x+9+x+10=11x+55}}}
{{{11x+55=143}}}
{{{11x=143-55}}}
{{{11x=88}}}
{{{x=8}}}............smallest integer in the set T, 

then the {{{largest}}} integer of the set T is {{{8+10=18}}}

check the median

{{{(8+18)/2=36/2=13}}}->which is true

so, answer is {{{B}}}) {{{18}}}