Question 1143620
My question is more about what rule to follow than calculations 
8÷2(2+2)
Do you use order of execution rules to solve
8÷2(2+2)=8÷2(4)=8÷2×4=4×4=16

Or do you use distributive law to solve

8÷2(2+2)=8÷(2×2+2×2)=8÷(4+4)=8÷8=1

Which answer is right and why and which answer is wrong and why
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Remember PEMDAS
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8÷2(2+2) is ambiguous, should be either 8÷(2(2+2)) or (8÷2)(2+2), so an argument can be made to support either "answer."
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If it's 8÷(2(2+2)) {{{8/(2*(2+2))}}}
--> 8÷(2*4)
= 8/8 = 1
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Notice I did say "if"