Question 1143570
Given equations:

1. x+2/y+1 = 1
*multiply both sides by y+1
   x+2 = y+1
   x = y-1

2. x-4/y-2 = 1/2
    2(x-4) = 1(y-2)
      2x-8 = y-2
      2x = y+6
*insert x = y-1 to equation above
      2(y-1)= y+6
      2y-2 = y+6 
         y = 8       
 So therefore, using x = y-1
      x = 8-1
      x = 7

Answer: 
x = 7 
y = 8

Testing:
x = 7 + 2 = 9
y = 8 + 1 = 9
9/9 = 1

x = 7 - 4 = 3
y = 8 - 2 = 6
3/6 = 1/2