Question 1143388
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            How this problem is worded,  printed,  posted and presented,  it  MAKES  NO  ANY  SENSE.



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{{{highlight(HOWEVER)}}}, if you want to find <U>THE SUM</U> of the coefficients "a", "b" and "c", then there is a beautiful way to do it.



Notice that for any quadratic polynomial  f(x) = ax^2 + bx + c,  the sum of its coefficients a + b + c is equal to 

    f(1) = a*1^2 + b*1 + c = a + b + c.



So, put x= 1 in the polynomial  (x-2)*(x+2)  to get the sum value


    a + b + c = (1-2)*(1+2) = -1*3 = 3.



<U>ANSWER</U>.  a + b + c = -3.
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