Question 1143407
Suppose a railroad rail is 4 kilometers and it expands on a hot day by 13 centimeters in length.
 Approximately how many meters would the center of the rail rise above the​ ground? 
:
change 4 km to 4000 meters, change 13 cm to .13 meters
this would form an isosceles triangle with a base of 4000 meters
then
{{{(4000+.13)/2}}} = 2000.065 meters, the equal sides
the altitude (a) of the triangle = the center of the rail rise
:
Using pythag on one of the two right triangles that are formed
a^2 + 2000^2 = 2000.065^2
:
a = {{{sqrt(2000.065^2 - 2000^2)}}}
a = 16 meters approximately