Question 1143408
What is the equation, in slope-intercept form, of the line that is perpendicular to the line 
y  -  4 =  -  (x  -  6) and passes through the point (−2, −2)? 
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----> y = -x + some constant, slope = -1
Lines perpendicular have a slope that's the negative reciprocal.
-(1/-1) = 1
m = 1
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y - y1 = m*(x - x1) where (x1,y1) is the point (-2,-2)
y + 2 = 1*(x+2)
y = x
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y = 1x + 0