Question 1143404
I find it easiest to first convert to base 10 then over to the final base:

134 (base 5) = {{{ 1*5^2 + 3*5^1 + 4*5^0 }}} = 44 (base 10)
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44 (base 10) = {{{ 1*2^5 + 0*2^4 + 1*2^3 + 1*2^2 + 0*2^1 + 0*2^0 }}} =  101100 (base 2)
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Started at {{{2^5}}} because {{{2^6 = 64 > 44 }}}