Question 1143210
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You are given the sums of the three ages two at a time:
T+C = 80
T+G = 98
C+G = 94<br>
You already have two good algebraic solutions; here is another method that might be a bit less work.<br>
(1) Add all three equations: 2(T+C+G) = 272
(2) Divide by 2: T+C+G = 136<br>
Now the age of each can be found by comparing this last equation to the original three equations:
G = (T+C+G)-(T+C) = 136-80 = 56
C = (T+C+G)-(T+G) = 136-98 = 38
T = (T+C+G)-(C+G) = 136-94 = 42