Question 104925
{{{(x^(4) y^(6) z^(12)/9^(-2) x^(3) y^(-8) z^(-9))^0}}}
Seems like a lot of smokescreening in the instructions. 
The entire problem hinges on that last exponent.
{{{u^0=1}}} Independent of what value u has. 
{{{(x^(4) y^(6) z^(12)/9^(-2) x^(3) y^(-8) z^(-9))^0=1}}}