Question 1142977
This is a binomial where we are looking at probability 0,1,2,3 out of 10 with p=0.54
so prob. 0 is .46^10 or 0.0004
prob. 1 is (10C1)(0.46^9)*.54=0.0050
prob. 2 is 10C2*0.46^8*.54^2=0.0263
prob.3 is 10C3*0.46^7*.54^3=0.0824

That sum is 0.1141

rough check with normal approximation
continuity correction factor use 3.5
mean is 5.4, variance is 5.4*.46 or 2.48, so sd is 1.58
z< (3.5-5.4)/1.58
z< -1.20
that probability is 0.1151