Question 1142990
the total budgeted is 1,740,000
P = pavement
B = base material
S = sidewalk
pavement costs twice the amount of the base material, therefore:
P = 2B
sidewalk costs one fourth the mount of the pavement, therefore:
S = P/4
since P = 2B, and since S = P/4, then  S = 2B/4 = B/2


you have:
P = 2B and S = B/2
you also have P + B + S = 1,740,000
replace P with 2B and S with B/2 and you get:
2B + B + B/2 = 1,740,000
multiply both sides of this equation by 2 to get:
4B + 2B + B = 1,740,000
combine like terms to get:
7B = 1,740,000*2 = 3,480,000
solve for B to get B = 3,480,000/7 = 497,142.8571.
P = 2B = 2*497,142.8571 = 994,285.7143.
S = B/2 = 497,142.8571/2 = 248,571.4286.
P + B + S = 1,740,000


the sidewalk should cost 248,571.4286.
that's your solution as best i can determine.
round to the nearest penny, it becomes 248,571.43.