Question 1142987
Let {{{ t }}} = time in hrs it takes when the
student arrives on time
Let {{{ d }}} = the distance in km to the school
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(1) {{{ d = 2.5*( t + 6/60 ) }}}
(1) {{{ d = 2.5t + .25 }}}
and
(2) {{{ d = 3*( t - 10/60 ) }}}
(2) {{{ d = 3t - .5 }}}
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{{{ 2.5t + .25 = 3t - .5 }}}
{{{ .5t = .75 }}}
{{{ t = 1.5 }}}
Plug this result back into (1) or (2)
(2) {{{ d = 3*1.5 - .5 }}}
(2) {{{ d = 4.5 - .5 }}}
(2) {{{ d = 4 }}}
The distance to school is 4 km
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check:
(1) {{{ d = 2.5t + .25 }}}
(1) {{{ 4 = 2.5*1.5 + .25 }}}
(1) {{{ 4 = 3.75 + .25 }}}
(1) {{{ 4 = 4 }}}
and
(2) {{{ 4 = 3*1.5 - .5 }}}
(2) {{{ 4 = 4.5 - .5 }}}
(2) {{{ 4 = 4 }}}
OK