Question 1142963
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Let *[tex \Large x] represent the first of the two consecutive odd integers.  Then the second of the two must be *[tex \Large x\ +\ 2].  The product of the two is *[tex \Large x^2\ +\ 2x] and this is given to equal 1023.  So:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x^2\ +\ 2x\ =\ 1023]


Which is to say:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ x^2\ +\ 2x\ -\ 1023\ =\ 0]


Solve the quadratic and sum the two roots.


Hint: *[tex \Large \sqrt{1023}\ \approx\ 31.98], so find the odd integers on either side of 32.
								
								
John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
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*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \  
								
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