Question 1142816
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By changing the origin for the time, you may forget about {{{alpha}}} and write the formula for SHM in the form


    x = {{{8*cos((pi/3)*t)}}}.


It is totally enough to solve the problem.


Now, when x= 5 cm, you have  5 = {{{8*cos((pi/3)*t)}}}, or


    {{{cos((pi/3)*t)}}} = {{{5/8}}}.


Next, the velocity is the DERIVATIVE of the position function x = x(t)


    Velocity = {{{d/(dt)}}}({{{8*cos((pi/3)*t)}}}) = {{{-8*(pi/3)*sin((pi/3)*t)}}}.


You just know the cosine function  {{{cos((pi/3)*t)}}}  from (1) - so you can calculate 

    {{{sin((pi/3)*t)}}} = {{{sqrt(1-(5/8)^2)}}}.


In this way, you can complete calculations for velocity.


Then for acceleration, use the fact that it is THE SECOND DERVATIVE of the position function and do the same.
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