Question 1142818
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{{{(p+1/p)^2}}} = {{{p^2}}} + {{{2p*(1/p)}}} + {{{(1/p)^2}}} = {{{p^2}}} + 2 + {{{(1/p)^2}}} = [ {{{p^2}}} - 2 + {{{(1/p)^2}}} ] + 4 = {{{(p-1/p)^2}}} + 4 = {{{5^2}}} + 4 = 25 + 4 = 29.    <U>ANSWER</U>
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