Question 1142790
.
<pre>

Having nothing else given, an appropriate hypothesis is to assume that we have random variable 


    X = "the number of failures per week" 


with integer random values which is uniformly distributed with the minimum value of 0 and the maximum value of 4.



Then the mean average  is exactly 2  (= {{{(0 + 1 + 2 + 3 + 4)/5}}} ), as the problem states, 

and  the condition becomes "consistent with the given part" and "self-closed".



Then the answer to the problem's question is   P(X <= 1) = {{{2/5}}}  (X may have values of 0 or 1  of 5 possible integer values from 0 to 4).  
</pre>

Solved.



-----------------


See the lesson

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/Probability-and-statistics/Unusual-probability-problems.lesson>Unusual probability problems</A> 

in this site, &nbsp;where you will find many other similar problems solved and explained.