Question 1142745
n, (n-1), (n-2) are the three numbers
:
the sum of three consecutive numbers is 117.
n + (n-1) + (n-2) = 117
3n - 3 = 117
3n = 117 + 3
3n = 120
 n = 120/3
 n = 40 is the biggest number.
:
:
Check: 40 + 39 + 38 = 117