Question 1142719
We know that the sine of x is 3/5.  We know that the sine is
opposite/hypotenuse.  So we draw a right triangle with angle x
and put the numerator of 3/5, which is 3 on the side opposite
the angle x and put the denominator of 3/5, which is 5, on the
hypotenuse.  We let the side adjacent to angle x be "a":

{{{drawing(160,100,-1,5,-1,4,

triangle(0,0,4,0,4,3),
locate(1,.8,x),
locate(2,0,a), locate(4.03,1.5,3),locate(1.6,2.3,5) )}}}

We calculate "a" by the Pythagorean theorem:

{{{a^2+b^2=c^2}}}
{{{a^2+3^2=5^2}}}
{{{a^2+9=25}}}
{{{a^2=16}}}
{{{sqrt(a^2)=sqrt(16)}}}
{{{a=4}}}

So we put 4 on the adjacent side:

{{{drawing(160,100,-1,5,-1,4,

triangle(0,0,4,0,4,3),
locate(1,.8,x),
locate(2,0,4), locate(4.03,1.5,3),locate(1.6,2.3,5) )}}}

The rest is plugging in formulas, for we know that

{{{sin(x)=3/5}}}, {{{cos(x)=4/5}}}, {{{tan(x)=3/4)}}}

Do you know the formulas?  Do you know how to plug in?
If not, ask how in the note form below and I'll get back
to you by email.