Question 1142718
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tan(x)*sin^2(x) = 2tan(x)  ====>


tan(x)*(sin^2(x) - 2) = 0.


Since sin^2(x) is always  LESS THAN  2,  it implies  tan(x) = 0.


The solutions to this equation are


    x = {{{k*pi}}},  k = 0, +/-1, +/-2, . . .  ("k" is any integer number).   <U>ANSWER</U>
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