Question 1142695
x = number of pounds of coffee worth 93 cents a pound.
y = number of pounds of coffee worth 120 cents a pound.


30 pound mixture = 102 cents a pound.


your 2 equations that need to be solved simultaneously are:


x + y = 30
93x + 120y = 102 * (x + y)


in the first equation, solve for y to get y = 30 - x.
in the second equation, replace y with 30 - x to get:
93 * x + 120 * (30 - x) = 102 * (x + 30 - x).
simplify to get:
93 * x + 3600 - 120 * x = 102 * x + 3060 - 102 * x.
combine like terms to get:
-27 * x + 3600 = 3060.
subtract 3600 from both sides of the equation to get:
-27 * x = -540.
solve for x to get x = 20.
since x + y = 30, then y has to be equal to 10.


your solution appears to be x = 20 and y = 10
in the first equation, x + y = 30 becomes 20 + 10 = 30 which becomes 30 = 30.
in the second equation, 93 * x + 120 * y = 102 * (x + y) becomes 93 * 20 + 120 * 10 = 102 * 30 which becomes 1860 + 1200 = 3060 which becomes 3060 = 3060.


solution looks good.
solution is that 20 pounds of 93 cents a pound coffee are mixed with 10 pounds of 120 cents a pound coffee to make 30 pounds 102 cents a pound coffee.


93 cents is equal to $.93.
120 cents is equal to $1.20.
102 cents is equal to $1.02.


you divide cents by 100 to get dollars.
you multiply dollars by 100 to get cents.