Question 1142641
lisa is five times older than her son. After 2 years, the sum of their ages will be 40, how old are they now?
------------
L = 6S now
---
In 2 years:
L+2 + (S+2) = 40
----
Sub for L
6S+2 + (S+2) = 40
7S = 36
----
No integer solution, becauce 5 times older is not 5 times as old.
------
1 time older = 100% more = 2 times as old
2 times older = 200% more = 3 times as old
.
.
5 times older = 500% more = 6 times as old
-----------------
PS  This is not your fault, no reflection on you.
It's another example of people writing math problems and math books who do not know the subject.
==================
You see things like "5 times smaller" and "10 times closer."
1 time smaller is zero, how can something be 5 times smaller?  Or 10 times closer?
-----
It's call gibberish.
Gibberish is not allowed in math.