Question 1142617
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The plane will crash if and only if one of the following events will happen


    - (a)  central and left engines fail

    - (b)  central and right engines fail

    - (c)  central and both left and right engines fail.



The probabilities for each of these events are


       P(a) = 0.005*0.008*(1-0.008) = 0.00003968

       P(b) = 0.005*0.008*(1-0.008) = 0.00003968

       P(c) = 0.005*0.008*0.008     = 0.00000032


The probability of the crash is the sum P = P(a) + P(b) + P(c) = 0.00007968 (approximately).    <U>ANSWER</U>
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