Question 1142602
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Let "n" be the number of stocks A and "m" be the number of stocks B.


Then from the condition you have this system of 2 equations in 2 unknowns


        40*n +   60*m = 36000    (1)

    1.5*40*n + 2*60*m = 66000.   (2)



Simplify


       40n +  60m = 36000        (3)

       60n + 120m = 66000        (4)


Simplify one more time by dividing all the terms by 20


       2n +  3m = 1800          (5)

       3n +  6m = 3300          (6)



Multiply eq(5) by 2 (both sides). Keep eq(6) as is.


       4n +  6m = 3600          (7)

       3n +  6m = 3300          (8)
   

Subtract eq(8) from eq(7)


        n       = 300.


Then from eq(7)   4*300 + 6m = 3600,   6m = 3600 - 1200 = 2400,   m = 2400/6 = 400.


<U>ANSWER</U>.  300 stocks A  and  400 stocks B.


<U>CHECK</U>.   You can check my solution and my answer by substituting these values m and n into the original equations.

         Do it on your own.
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Solved.