Question 1142552
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P(at least one face card) = 1 - P(no face cards)<br>
So calculate the probability of getting no face cards when 3 cards are drawn:<br>
P(first card not a face card) = 40/52
P(second card not a face card) = 39/51
P(third card not a face card) = 38/50<br>
P(no face cards) = (40/52)(39/51)(38/50) = .447 to 3 decimal places<br>
So P(at least one face card = 1-.447 = .553