Question 1142537
 one number is 3 less than a second number.
a = b - 3
 twice the second number is 4 less than 3 times the first.
2b = 3a - 4
replace a with (b-3) from the first equation
2b = 3(b-3) - 4
2b = 3b = - 9 - 4
2b - 3b = -13
-b = -13
b = 13
a is 3 less, therefore 
a = 10
 find the smaller of the two numbers: 10
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Check using the 2nd equation
 2(13) = 3(10) - 4
26 = 30 - 4

 
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