Question 1142494
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6.1  Sorry... tree diagrams don't work very well in typed text.  You can do that part.<br><pre>
A1:  machine A  and  defective:     0.20*0.01 = 0.0020
A2:  machine A  and  not defective: 0.20*0.99 = 0.1980

B1:  machine B  and  defective:     0.30*0.02 = 0.0060
B2:  machine B  and  not defective: 0.30*0.98 = 0.2940

C1:  machine C  and  defective:     0.50*0.06 = 0.0300
C2:  machine C  and  not defective: 0.50*0.94 = 0.4700
                                           ---------
                                             1.0000</pre>
6.2<br>
(a) B2 from the table<br>
(b) A1+B1+C1 from the table